Hybridisation sp sp2 sp3 sp3d sp3d2 - UNSOLVED PRACTICE SET
Chapter: Chemical Bonding and Molecular Structure | Topic: Hybridisation sp sp2 sp3 sp3d sp3d2
HYBRIDISATION SP SP2 SP3 SP3D SP3D2 - UNSOLVED PRACTICE SET
Topic: Hybridisation sp sp2 sp3 sp3d sp3d2
Multiple Choice Questions
Q1. Hybridisation involves:
- Mixing of atomic orbitals of different energies to form new orbitals of equivalent energy
- Mixing of atomic orbitals of the same energy
- Separation of atomic orbitals
- Destruction of atomic orbitals
Q2. The shape of a molecule with sp hybridisation is:
- Tetrahedral
- Trigonal planar
- Linear
- Octahedral
Q3. In sp² hybridisation, the orbitals are oriented at:
- 109.5° to each other
- 120° to each other
- 90° to each other
- 180° to each other
Q4. The hybridisation of carbon in methane (CH₄) is:
- sp
- sp²
- sp³
- sp³d
Q5. The hybridisation of phosphorus in PCl₅ is:
- sp³
- sp³d
- sp³d²
- dsp²
Q6. The number of hybrid orbitals formed is always:
- Less than the number of atomic orbitals mixed
- Equal to the number of atomic orbitals mixed
- More than the number of atomic orbitals mixed
- Independent of the number of atomic orbitals
Short Answer Questions
Q7. Define hybridisation. Why do atoms undergo hybridisation?...
Q8. Predict the hybridisation of the central atom in:
(a) BeCl₂
(b) BF₃
(c) CH₄
Q9. Differentiate between sp, sp², and sp³ hybridisation on the basis of:
(a) Number of orbitals mixed
(b) Geometry
(c) Bond angle
Q10. Why does carbon in ethene (C₂H₄) use sp² hybridisation instead of sp³?
Q11. Your art teacher mixes red, blue, and yellow paints to create new colours for a painting. She explains that hybridisation is similar — atomic orbitals mix to create new orbitals with different shapes and properties. If she mixes one s and one p orbital, what "colour" (geometry) does she get? What if she mixes one s and three p orbitals?
Q12. What is the hybridisation of sulphur in SF₆? Explain how sulphur can expand its octet to accommodate this hybridisation.
Long Answer Questions
Q13. Explain the concept of hybridisation with suitable examples. Describe the formation of:
(a) sp hybrid orbitals (BeCl₂)
(b) sp² hybrid orbitals (BF₃)
(c) sp³ hybrid orbitals (CH₄)
(d) sp³d hybrid orbitals (PCl₅)
(e) sp³d² hybrid orbitals (SF₆)
For each, show the orbital diagram and predict the geometry.
Q14. Discuss the relationship between hybridisation and molecular geometry. Explain how to determine the hybridisation of a central atom using:
(a) The steric number method
(b) The number of sigma bonds and lone pairs
Predict the hybridisation, shape, and bond angles of:
(a) NH₃
(b) H₂O
(c) CO₂
(d) SO₂
Q15. During a chemistry workshop, students are debating the structure of ethyne (C₂H₂).
(a) One student draws the structure H-C≡C-H and claims both carbons are sp hybridised. Verify this using the steric number method.
(b) Explain why the C-C bond in ethyne is shorter and stronger than in ethene or ethane, using hybridisation concepts.
(c) In benzene (C₆H₆), all carbon atoms are sp² hybridised. Explain how this leads to the planar hexagonal structure and the delocalized π electron system.
(d) A student asks: "If diamond has sp³ hybridised carbon and graphite has sp² hybridised carbon, can we have a form of carbon with sp hybridised atoms?" How would you answer, considering carbon allotropes?
Numerical / Application-Based Problems
Q16. Determine the hybridization of the central atom in the following molecules/ions using the steric number method. Show your calculation.
(a) CO₂
(b) NH₄⁺
(c) SO₂
(d) IF₇
(e) XeO₃F₂
Q17. The C-C bond lengths in different hydrocarbons are:
Ethane (C-C single): 154 pm
Ethene (C=C double): 134 pm
Ethyne (C≡C triple): 120 pm
(a) Explain the trend in bond lengths using hybridisation (sp³, sp², sp).
(b) Calculate the percentage decrease in bond length from ethane to ethene, and from ethene to ethyne.
(c) The C-H bond length in ethane is 109 pm, in ethene is 108 pm, and in ethyne is 106 pm. Explain this trend.
(d) Why does greater s-character in the hybrid orbital lead to shorter and stronger bonds?
Q18. Consider the following molecules and answer the questions:
(a) In CO₂, the carbon atom is sp hybridised. Draw the orbital overlap diagram showing how the two sigma bonds and two pi bonds form.
(b) In ethene (C₂H₄), each carbon is sp² hybridised. Calculate the percentage of s-character and p-character in each hybrid orbital.
(c) In NH₃, nitrogen is sp³ hybridised but the bond angle is 107° instead of 109.5°. Explain this deviation using the concept of lone pair-bond pair repulsion.
(d) In PCl₅, phosphorus uses sp³d hybridisation. Explain why the axial P-Cl bonds (240 pm) are longer than the equatorial P-Cl bonds (202 pm).