Equilibrium Constant Kc and Kp - UNSOLVED PRACTICE SET
Chapter: Equilibrium | Topic: Equilibrium Constant Kc and Kp
EQUILIBRIUM CONSTANT KC AND KP - UNSOLVED PRACTICE SET
Topic: Equilibrium Constant Kc and Kp
Multiple Choice Questions
Q1. For the reaction N₂(g) + 3H₂(g) ⇌ 2NH₃(g), the equilibrium constant Kc is expressed in terms of:
- Partial pressures
- Molar concentrations
- Mole fractions
- Mass of reactants and products
Q2. The equilibrium constant Kp is related to partial pressures for gaseous reactions. For the reaction 2SO₂(g) + O₂(g) ⇌ 2SO₃(g), Kp is:
- (P_SO₃)² / (P_SO₂)²(P_O₂)
- (P_SO₂)²(P_O₂) / (P_SO₃)²
- (P_SO₃) / (P_SO₂)(P_O₂)
- (P_SO₂)(P_O₂) / (P_SO₃)
Q3. The units of Kc for the reaction 2A(g) + B(g) ⇌ C(g) are:
- mol/L
- L/mol
- L²/mol²
- mol²/L²
Q4. If the equilibrium constant Kc for a reaction is very large (Kc >> 1), it indicates that:
- The reaction hardly proceeds
- The equilibrium lies far to the left
- The equilibrium lies far to the right
- The reaction is at equilibrium
Q5. For a reaction where Δn = 0 (no change in moles of gas), the relationship between Kp and Kc is:
- Kp = Kc(RT)
- Kp = Kc(RT)²
- Kp = Kc
- Kp = Kc/(RT)
Q6. The value of the equilibrium constant for a given reaction:
- Changes with the initial concentrations
- Changes with the presence of a catalyst
- Depends only on temperature
- Depends on the pressure
Short Answer Questions
Q7. Write the expressions for Kc and Kp for the reaction: 2NO(g) + O₂(g) ⇌ 2NO₂(g). What are the units of Kc and Kp for this reaction?
Q8. For the reaction H₂(g) + I₂(g) ⇌ 2HI(g), Kc = 54.3 at 700 K. What does this value tell you about the position of equilibrium? Does Kc have units in this case?
Q9. Explain why the equilibrium constant has a fixed value at a given temperature, even though the initial concentrations of reactants may vary.
Q10. A reaction has Kc = 1.0 × 10⁻⁵ at 298 K. Is the forward reaction favoured at this temperature? Explain your answer.
Q11. For the decomposition of PCl₅: PCl₅(g) ⇌ PCl₃(g) + Cl₂(g), write expressions for Kc and Kp. How are they related?
Q12. Can the equilibrium constant Kc ever be negative? Explain with reasoning.
Section C: Long Answer Questions
Long Answer Questions
Q13. (a) Define equilibrium constant Kc and Kp. For what type of reactions is Kp used instead of Kc?
(b) Derive the relationship between Kp and Kc for a general gaseous reaction.
(c) For the reaction N₂(g) + O₂(g) ⇌ 2NO(g), Kp = 4.0 × 10⁻⁴ at 2000 K. Calculate Kc at the same temperature. (R = 0.0821 L·atm/K·mol)
Q14. (a) Explain the significance of the magnitude of the equilibrium constant. How does the value of K help predict the extent of a reaction?
(b) For the reaction: H₂(g) + CO₂(g) ⇌ H₂O(g) + CO(g), Kc = 4.40 at 2000 K. In a 2.0 L container, 0.20 mol of H₂ and 0.20 mol of CO₂ are mixed. Calculate the equilibrium concentrations of all species.
(c) What happens to the value of Kc if a catalyst is added to the system? Explain.
Q15. (a) Explain why the equilibrium constant is independent of:
(i) Initial concentrations
(ii) Presence of a catalyst
(iii) Pressure (for reactions where Δn = 0)
(b) For the reaction: 2NO₂(g) ⇌ N₂O₄(g), Kp = 6.8 at 298 K. Calculate Kc for this reaction.
(c) A student claims that if the volume of the container is doubled, the value of Kc will decrease by half. Is the student correct? Explain your answer.
Numerical / Application-Based Problems
Q16. For the reaction: CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g)
At 700 K, Kc = 5.10. Initially, 1.00 mol of CO and 1.00 mol of H₂O are placed in a 2.00 L container.
(a) Set up an ICE table for this equilibrium.
(b) Calculate the equilibrium concentrations of all species.
(c) Calculate the value of Kp at 700 K.
(d) What percentage of CO has been converted to CO₂ at equilibrium?
Q17. The dissociation of phosphorus pentachloride is given by:
PCl₅(g) ⇌ PCl₃(g) + Cl₂(g)
At 250°C, Kp = 1.80 atm.
(a) Calculate Kc for this reaction at 250°C.
(b) If 0.20 mol of PCl₅ is placed in a 1.0 L flask, calculate the degree of dissociation (α) at equilibrium.
(c) Calculate the partial pressures of all species at equilibrium.
(R = 0.0821 L·atm/K·mol)
Q18. In India, the production of ammonia via the Haber process is crucial for fertiliser manufacturing:
N₂(g) + 3H₂(g) ⇌ 2NH₃(g)
At 500 K, Kp = 1.5 × 10⁻⁵.
(a) Calculate Kc at 500 K.
(b) In an industrial reactor, the initial partial pressures are: P_N₂ = 50 atm, P_H₂ = 150 atm, P_NH₃ = 0. Calculate the equilibrium partial pressure of NH₃ if the total pressure is maintained at 200 atm.
(c) The industrial process operates at 450-500°C and 200 atm. Explain why a compromise temperature is chosen, considering both thermodynamic (Kp) and kinetic factors.
(d) A student suggests operating at 800 K to increase the reaction rate. What would happen to the equilibrium yield of ammonia? Calculate Kc at 800 K if Kp = 2.5 × 10⁻⁷ at this temperature, and comment on the feasibility.