Heat Engine and Efficiency - UNSOLVED PRACTICE SET
Chapter: Thermodynamics | Topic: Heat Engine and Efficiency
HEAT ENGINE AND EFFICIENCY - UNSOLVED PRACTICE SET
Topic: Heat Engine and Efficiency
Multiple Choice Questions
Q1. The efficiency of a heat engine is defined as the ratio of:
- Heat absorbed to heat rejected
- Heat rejected to heat absorbed
- Work done to heat absorbed
- Work done to heat rejected
Q2. A heat engine absorbs 1000 J of heat and rejects 600 J to the sink. Its efficiency is:
- 60%
- 40%
- 100%
- 0%
Q3. The efficiency of any heat engine is always:
- Greater than 1
- Equal to 1
- Less than 1
- Equal to 0
Q4. In a heat engine, the working substance:
- Must be an ideal gas
- Must be a liquid
- Can be any substance
- Must be a solid
Q5. The area enclosed by the cycle on a P-V diagram for a heat engine represents:
- Heat absorbed
- Heat rejected
- Net work done
- Change in internal energy
Q6. A diesel generator in a rural Indian school provides backup power. If it absorbs 5000 J of heat from fuel combustion and does 1500 J of useful work per cycle, its efficiency is:
- 30%
- 70%
- 50%
- 15%
Short Answer Questions
Q7. Define the efficiency of a heat engine. Write its expression in terms of Qโ (heat absorbed) and Qโ (heat rejected).
Q8. Explain why the efficiency of a heat engine can never be 100%, even if there are no friction or other mechanical losses.
Q9. Draw a schematic diagram of a heat engine, labeling the source, sink, working substance, and the direction of heat and work flow.
Q10. What is a thermal reservoir? Why is it important in the analysis of heat engines?
Q11. A heat engine has an efficiency of 25%. If it rejects 600 J of heat per cycle, how much heat does it absorb? Show your calculation.
Q12. Explain the difference between a reversible heat engine and an irreversible heat engine. Give one example of each.
Long Answer Questions
Q13. Describe the working of a heat engine with a neat labeled diagram. Define efficiency and derive the expression ฮท = 1 โ (Qโ/Qโ). Explain the significance of each term and discuss why real engines always have lower efficiency than the theoretical maximum.
Q14. A heat engine operates in a cycle, absorbing heat Qโ from a source at temperature Tโ and rejecting heat Qโ to a sink at temperature Tโ.
(i) Draw the P-V diagram for a simple cyclic process.
(ii) Explain how the net work done is related to the area enclosed by the cycle.
(iii) If the engine absorbs 2000 J and rejects 1200 J, calculate the efficiency and work done.
(iv) What would be the maximum possible efficiency if Tโ = 600 K and Tโ = 300 K?
Q15. Consider two heat engines: Engine A operates between 800 K and 400 K with 40% efficiency, and Engine B operates between 600 K and 300 K with 35% efficiency.
(i) Calculate the Carnot efficiency for each engine.
(ii) Compare the actual efficiency to the Carnot efficiency for each.
(iii) Which engine is closer to being an ideal reversible engine?
(iv) What factors prevent real engines from achieving Carnot efficiency?
Numerical / Application-Based Problems
Q16. A heat engine operates between a source at 500 K and a sink at 300 K. In each cycle, it absorbs 1500 J of heat from the source.
(i) Calculate the maximum possible (Carnot) efficiency of this engine.
(ii) Calculate the maximum work that can be obtained per cycle.
(iii) If the actual efficiency is 60% of the Carnot efficiency, calculate the actual work done and heat rejected per cycle.
(iv) Calculate the actual heat rejected to the sink.
Q17. An automobile engine (petrol engine) operates in a cycle and has the following specifications:
Heat absorbed from combustion per cycle: 2000 J
Heat rejected to the exhaust per cycle: 1400 J
Number of cycles per second: 50
Calculate:
(i) The work done per cycle
(ii) The efficiency of the engine
(iii) The power output of the engine in watts
(iv) The total heat rejected per second
(v) If the fuel provides 4 ร 10โท J per kg, and the engine consumes 0.5 kg of fuel per hour, calculate the overall efficiency of the engine.
Q18. A proposed heat engine design claims to operate between 400 K and 300 K with an efficiency of 30%. The designer says it uses a special working fluid that avoids the usual limitations.
(i) Calculate the Carnot efficiency for these temperatures.
(ii) Is the claimed efficiency possible? Justify your answer using the Second Law of Thermodynamics.
(iii) If the engine absorbs 1000 J per cycle, calculate the maximum work it can actually do.
(iv) What advice would you give to the designer?