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Metre Bridge and Potentiometer - UNSOLVED PRACTICE SET

Class 12

Chapter: Current Electricity | Topic: Metre Bridge and Potentiometer

Study Material.
Class 12

METRE BRIDGE AND POTENTIOMETER - UNSOLVED PRACTICE SET

Topic: Metre Bridge and Potentiometer

Time: 40 mins | Marks: 30 | Difficulty: Medium

Multiple Choice Questions

Q1. A metre bridge works on the principle of:

  1. Ohm's Law
  2. Wheatstone bridge
  3. Kirchhoff's Laws
  4. Faraday's Law

Q2. In a metre bridge, the unknown resistance X is connected in the:

  1. Right gap
  2. Left gap
  3. Both gaps
  4. Neither gap

Q3. The balance condition for a metre bridge is:

  1. X/R = l/(100 โˆ’ l)
  2. X/R = (100 โˆ’ l)/l
  3. X + R = l
  4. X ร— R = l

Q4. A potentiometer measures potential difference by:

  1. Drawing current from the source
  2. Comparing with a known potential difference without drawing current
  3. Using a galvanometer in series
  4. Measuring resistance first

Q5. The sensitivity of a potentiometer can be increased by:

  1. Increasing the EMF of the driver cell
  2. Decreasing the length of the potentiometer wire
  3. Increasing the length of the potentiometer wire
  4. Using a thicker wire

Q6. In a potentiometer experiment, the balancing length for a cell is 60 cm. If the EMF of the driver cell is doubled, the new balancing length will be:

  1. 30 cm
  2. 60 cm
  3. 120 cm
  4. Unchanged

Short Answer Questions

Q7. Draw a labelled diagram of a metre bridge. Explain why it is called a "metre" bridge.

Q8. In a metre bridge experiment, the balance point is found at 40 cm from the left end. The known resistance in the right gap is 12 ฮฉ. Calculate the unknown resistance.

Q9. Why is a potentiometer preferred over a voltmeter for measuring EMF of a cell? Explain the key advantage.

Q10. What is meant by the "potential gradient" of a potentiometer wire? On what factors does it depend?

Q11. A potentiometer wire of length 100 cm has a resistance of 5 ฮฉ. It is connected to a driver cell of 2 V. Calculate the potential gradient.

Q12. Why is it important that the EMF of the driver cell in a potentiometer be greater than the EMF of the cell being measured?

Long Answer Questions

Q13. Explain the principle and working of a metre bridge for measuring unknown resistance. Derive the formula used. Why are thick copper strips used for the gaps and the balance point?

Q14. Explain the principle and working of a potentiometer. Why is it called a "null method" instrument? How does it measure EMF without drawing current from the source?

Q15. In a metre bridge experiment, the unknown resistance X is placed in the left gap and a known resistance R = 10 ฮฉ in the right gap. The balance point is found at 60 cm from the left end.

(a) Calculate the unknown resistance X.

(b) If the resistances are interchanged, where will the new balance point be?

(c) Calculate the resistance of the metre bridge wire if it has uniform resistance per unit length of 0.1 ฮฉ/cm.

(d) Explain why the balance point should ideally be near the middle of the wire for maximum accuracy.

Numerical / Application-Based Problems

Q16. In your school physics lab, you perform a metre bridge experiment to find the resistance of a wire. The wire is placed in the left gap and a resistance box in the right gap. The following readings are obtained:

Table

R (ฮฉ) Balance point l (cm)

5 75.0

10 60.0

15 50.0

20 42.9

(a) Calculate the unknown resistance X for each reading using the metre bridge formula.

(b) Find the mean value of X and estimate the percentage error.

(c) Plot a graph of (100 โˆ’ l)/l versus R. What should be the shape of this graph?

(d) From the graph, determine X and compare with the mean value.

(e) Explain why taking multiple readings improves accuracy.

Q17. A potentiometer wire of length 200 cm and resistance 10 ฮฉ is connected to a driver cell of EMF 3 V with internal resistance 1 ฮฉ. A standard cell of EMF 1.08 V is being measured.

(a) Calculate the potential gradient along the wire.

(b) Find the balancing length for the standard cell.

(c) A student cell of unknown EMF E gives a balancing length of 144 cm. Calculate E.

(d) If the driver cell is replaced by one with EMF 5 V, what is the new balancing length for the student cell?

(e) Explain why the potentiometer method gives the true EMF, not just the terminal voltage.

Q18. In a school project, a student builds a potentiometer using a nichrome wire of length 300 cm and diameter 0.5 mm. The wire is connected to a 4 V battery.

(a) Calculate the resistance of the wire. [Given: ฯ_nichrome = 1.1 ร— 10โปโถ ฮฉ m]

(b) Calculate the potential gradient.

(c) The student uses this potentiometer to compare the EMFs of two cells. Cell A gives balance at 120 cm and Cell B at 180 cm. Find the ratio E_A/E_B.

(d) If Cell A has internal resistance 0.5 ฮฉ and gives balance at 115 cm when shunted with 10 ฮฉ, calculate the internal resistance using the formula.

(e) Explain why the potentiometer is ideal for comparing EMFs but not for measuring internal resistance directly without a shunt.


Total: 30 Marks | Time: 40 mins

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