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Crystal Field Theory - Octahedral and Tetrahedral - UNSOLVED PRACTICE SET

Class 12

Chapter: Coordination Compounds | Topic: Crystal Field Theory Octahedral and Tetrahedral

Study Material.
Class 12

CRYSTAL FIELD THEORY - OCTAHEDRAL AND TETRAHEDRAL - UNSOLVED PRACTICE SET

Topic: Crystal Field Theory Octahedral and Tetrahedral

Time: 40 mins | Marks: 30 | Difficulty: Medium

Multiple Choice Questions

Q1. In an octahedral crystal field, the d-orbitals split into:

  1. Three orbitals of lower energy and two of higher energy
  2. Two orbitals of lower energy and three of higher energy
  3. All five orbitals of equal energy
  4. Four orbitals of lower energy and one of higher energy

Q2. The energy difference between t₂g and eg sets in an octahedral field is called:

  1. Crystal field splitting energy (Δ₀)
  2. Pairing energy (P)
  3. Exchange energy
  4. Lattice energy

Q3. In a tetrahedral crystal field, the splitting pattern is:

  1. The same as octahedral but with larger Δ
  2. The same as octahedral but with smaller Δ
  3. Reverse of octahedral with smaller Δ
  4. Reverse of octahedral with larger Δ

Q4. For the same metal and ligands, the relationship between octahedral and tetrahedral splitting is approximately:

  1. Δt = Δ₀
  2. Δt = (4/9)Δ₀
  3. Δt = 2Δ₀
  4. Δt = (9/4)Δ₀

Q5. In an octahedral field, the t₂g orbitals are:

  1. dx²-y² and dz²
  2. dxy, dyz, and dzx
  3. dx²-y², dxy, and dz²
  4. dyz, dzx, and dx²-y²

Q6. Strong field ligands cause:

  1. Small crystal field splitting
  2. Large crystal field splitting
  3. No crystal field splitting
  4. Equal splitting in all geometries

Short Answer Questions

Q7. Explain the splitting of d-orbitals in an octahedral crystal field. Which orbitals are raised in energy and which are lowered?

Q8. Why is the crystal field splitting energy (Δ₀) larger for strong field ligands than for weak field ligands?

Q9. In a tetrahedral complex, why is the crystal field splitting opposite to that in an octahedral complex? Explain with a diagram description.

Q10. What is meant by the spectrochemical series? Arrange the following ligands in increasing order of crystal field splitting ability: I⁻, H₂O, NH₃, CN⁻, Cl⁻.

Q11. Explain why tetrahedral complexes are rarely low-spin (inner orbital) complexes.

Q12. Draw a rough crystal field splitting diagram for d⁴ configuration in an octahedral field for both strong field and weak field cases. Label the electron distribution.

Long Answer Questions

Q13. Explain Crystal Field Theory for octahedral complexes. Discuss:

(a) The splitting of d-orbitals in an octahedral field

(b) The difference between strong field and weak field ligands

(c) How CFT explains the formation of high-spin and low-spin complexes

Illustrate with examples.

Q14. (a) Explain the splitting of d-orbitals in a tetrahedral crystal field. Why is Δt smaller than Δ₀?

(b) Why are tetrahedral complexes generally high-spin? Explain using the concepts of Δt and pairing energy.

(c) Give an example of a tetrahedral complex and predict whether it will be coloured or colourless.

Q15. (a) Compare crystal field splitting in octahedral and tetrahedral complexes with respect to:

(i) The pattern of splitting

(ii) The magnitude of splitting

(iii) The possibility of high-spin and low-spin complexes

(b) For a d⁶ configuration, draw the crystal field splitting diagrams for:

(i) High-spin octahedral complex

(ii) Low-spin octahedral complex

(iii) Tetrahedral complex

Numerical / Application-Based Problems

Q16. The crystal field splitting energy Δ₀ for [Ti(H₂O)₆]³⁺ is 20,300 cm⁻¹.

(a) Calculate the wavelength of light absorbed by this complex.

(b) Predict the colour of the complex. (Hint: The colour observed is complementary to the colour absorbed.)

(c) Why does this complex show only one d-d transition?

(d) If the ligand is changed from H₂O to CN⁻, would Δ₀ increase or decrease? Explain.

Q17. Consider the following octahedral complexes:

[CoF₆]³⁻: High spin, Δ₀ = 13,000 cm⁻¹

[Co(NH₃)₆]³⁺: Low spin, Δ₀ = 23,000 cm⁻¹

[Co(CN)₆]³⁻: Low spin, Δ₀ = 34,000 cm⁻¹

(a) For each complex, show the electron distribution in t₂g and eg orbitals.

(b) Calculate the crystal field stabilization energy (CFSE) for each complex.

(c) Explain why F⁻ forms a high-spin complex while CN⁻ forms a low-spin complex with Co³⁺.

(d) Arrange these ligands in the spectrochemical series based on the given data.

Q18. In a school laboratory, students are given four solutions containing different octahedral complexes of Co³⁺:

Solution A: [CoF₆]³⁻ — green

Solution B: [Co(H₂O)₆]³⁺ — blue

Solution C: [Co(NH₃)₆]³⁺ — yellow

Solution D: [Co(CN)₆]³⁻ — colourless

(a) Explain the origin of colour in these complexes using CFT.

(b) Arrange these complexes in order of increasing crystal field splitting energy (Δ₀). Give reasoning.

(c) Why is [Co(CN)₆]³⁻ colourless? Explain using the concept of d-d transitions.

(d) If you were to replace Co³⁺ with Fe²⁺ (d⁶) in an octahedral field with NH₃ ligands, would you expect a high-spin or low-spin complex? Explain using CFT.


Total: 30 Marks | Time: 40 mins

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